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kiruha [24]
3 years ago
12

I need help with this

Mathematics
1 answer:
Semenov [28]3 years ago
7 0
The answer is B girl
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A resort had 380 rooms with space for 6 people. Estimate the greatest number of people who could be in these rooms at the same t
LenaWriter [7]

Answer: 2400 people.


Step-by-step explanation:

1. To solve this problem you must round 380 to its greatest place.

2.  As you can see, 380 is closer to 400, therefore, you can round it up to 400.

3. Keeping this on mind, you must multiply 400 rooms by 6 people, as following:

(400)(6)=2400

4. Therefore, as you can see, the result indicates that the greatest number of people who could be in these rooms at the same time is 2400.


6 0
4 years ago
Help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
diamong [38]

Answer:

28

Step-by-step explanation:

You times 8/3 and 21/2 to get 28

5 0
3 years ago
1.4t-0.4(t-3.1)=5.8 please help !!
Svetllana [295]
Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56
4 0
4 years ago
HELP MEEE please<br> NO BOTS
neonofarm [45]

Answer:

64

Step-by-step explanation:

You'd put 64 in the box because the x is the original number (4). example: 4^3 = 64, ^3(insert the root sign) 64 = 4

sorry in advanced, I dont have the math signs to make the equations

6 0
1 year ago
(U...
Tresset [83]

Answer:

the 19th term of the arithmetic sequence is 73.

Step-by-step explanation:

Given:

The arithmetic sequence whose common difference is

d=4

And first term is

a=1

Find the 19th term of the arithmetic sequence

n=19

Now we know that,

a_{n}=a+(n-1)d

Put all the value in above AP.

a_{19}= 1+(19-1)4

a_{19}= 1+18\times 4

a_{19}= 1+72

a_{19}= 73

So, 19_{th} term of the sequence is 73.

3 0
3 years ago
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