$\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}$

$\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5$

7 0

3 years ago

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Write an equation of the line passing through point P(−8, 0) that is perpendicular to the line 3x−5y = 6.

denpristay [2]

Answer:

y = -5/3 * x - 40/3

Step-by-step explanation:

A perpendicular line has an opposite and a reciprocal of the slope.

Your equation should be:

-5y = -3x +6

Divide all parts by -5.

y = 3/5x - 6/5

Since the perpendicular line has an opposite and a reciprocal of the slope, the slope will be -5/3.

Now you must make an equation in point-slope form. This is an example of that form. You will need at least one point to make this equation work. In this case we have (-8,0).

In put the y and x coordinates like this:

y - 0 = -5/3(x - (-8)

Start solving the equation.

y - 0 = -5/3(x + 8)

y - 0 = -5/3 * x - 40/3

y = -5/3 * x - 40/3

This is your equation.

y = -5/3 * x - 40/3

(You can make it -5/3x in your answer but it looks weird online. You may think that it is -5 divided by 3 times x, but it actually is 5/3 times x. That's why I wrote it as y = -5/3 * x - 40/3)

8 0

2 years ago

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One step equations word problems. I ONLY NEED 3-8!!!!

viva [34]

3: 18
4: 17
5: 561
6: 17
7: 23
:)

5 0

3 years ago