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3 years ago

Suppose you got 3 out of every 4 questions

Mathematics

2 answers:

Andrej [43]3 years ago

7 0

Answer:

16 questions

Step-by-step explanation:

12÷3/4

12×4/3

48/3=16

masya89 [10]3 years ago

3 0

Answer:

16 questions

Step-by-step explanation:

Basically for every group of four questions you get three right. So first find the amount of groups of three.

12/3=4

Than multiply by four to find total amount of questions.

4*4=16

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One of the legs of a right triangle measures 4 cm and its hypotenuse measures 18 cm. Find the measure of the other leg. If neces

Aleks04 [339]

Answer:

√308 or 17.5

Step-by-step explanation:

c^2=a^2+b^2

c^2-a^2=b^2

Substitute

18^2-4^2=b^2

324-16=b^2

b^2=308

b=√308 or b=17.5

7 0

3 years ago

Solve the system by using the inverse of the coefficient matrix. -3x + 9y = 9 3x + 2y = 13 Group of answer choices

kirill [66]

Answer:

x= 3

y=2

Step-by-step explanation:

-3x + 9y = 9 ----------- equation 1

3x + 2y = 13--------------- equation 2

In Matrix Form

$\left[\begin{array}{cc}-3&9\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}9\\13\end{array}\right]$

Let A = $\left[\begin{array}{cc}-3&9\\3&2\end{array}\right]$ X = $\left[\begin{array}{c}x\\y\end{array}\right]$ and B = $\left[\begin{array}{c}9\\13\end{array}\right]$

Then Mathematically AX= B

or X= A⁻¹ B

Where A⁻¹ = Adjacent A/ mod of A

Adjacent A = $\left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]$

Mod Of A= -6 - (27) = -33 which is not equal to zero

so Putting These values in the given formula

X= 1/-33 $\left[\begin{array}{cc}2&-9\\-3&-3\end{array}\right]$ $\left[\begin{array}{c}9\\13\end{array}\right]$

Now Multiplying Rows and Columns

$\left[\begin{array}{c}x\\y\end{array}\right]$ = -1/33 $\left[\begin{array}{cc}2*9+- 9*13\\-3*9 +- 3*13\end{array}\right]$

Solving the Matrix we get

$\left[\begin{array}{c}x\\y\end{array}\right]$ = -1/33 $\left[\begin{array}{cc}18-117\\-27-39\\\end{array}\right]$

$\left[\begin{array}{c}x\\y\end{array}\right]$ = -1/33 $\left[\begin{array}{cc}-99\\-66\end{array}\right]$

From Here we find x= 99/33 or 3

and y = 66/33= 2

4 0

3 years ago

Theoretically, if a month is chosen 300 times,

horsena [70]

Answer:

75 times.

Step-by-step explanation:

Well there are 12 months and 3 of them start with the letter J, so theoretically, 25% of the months chosen will start with the letter J because $\frac{3}{12}=\frac{1}{4}$ , which is 25%. 25% of 300 (or $\frac{300}{4}$ , for those who like fractions) is 75, so theoretically, we can expect a month that starts with the letter J 75 times.