Answer:
Vertex: (3,0)
Max/min: min
axis of symmetry: x=3
Domain: (-∞,∞)
Range: [3,∞)
zeroes: (3,0)
Step-by-step explanation:
Vertex is where the graph changes directions (so in this case it's the point where it changes from decreasing to increasing) which I think is (3,0)
It's a minimum because the coefficent for the degree is positive
The axis of symmetry is just the x value of the vertex (which is x= 3)
the domain is all possible x values (-∞,∞)
The range is all possible y values [3,∞)
The zeroes is where the line hits the x axis, which is (3,0)
Answer: The radius is 12.54 feet, and the diameter is 25.08 feet.
Explanation: By applying the circumference into the equation r = 
, we get r = 
which simplifies the radius. And since radius is half of diameter, we multiply by 2 to get the diameter as well to solve the other blank in the problem.
Hope this helps! :D
Answer:
Step-by-step explanation:
Let chocolate bar = c and blow pops = b
<u>As per given we have equations below:</u>
- 5c + 8b = 23.25
- 2c + 13b = 21.55
<u>13 times the first equation minus 8 times the second to eliminate b and find c:</u>
- 13(5c + 8b) - 8(2c + 13b) = 13(23.25) - 8(21.55)
- 65c - 16c = 129.85
- 49c = 129.85
- c = 129.85/49
- c = 2.65
Each chocolate bar costs $2.65
M < PQS + m < RQS = 180° because they are supplementary angles.
Therefore:
(3x + 3) + (x + 19) = 180
3x — 3 + x + 19 = 180
4x + 16 = 180
Subtract 16 from both sides
4x — 16 = 180 — 16
4x = 164
Divide both sides by 4:
4x/4 = 164/4
x = 41
Therefore, the correct answer is x = 41
Point slope form follows the equation y-y₁=m(x-x₁), so we want it to look like that. Starting off with m, or the slope, we can find this using your two points with the formula
. Note that y₁ and x₁ are from the same point, but it does not matter which point you designate to be point 1 and point 2. Thus, we can plug our numbers in - the x value comes first in the equation, and the y value comes second, so we have
as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m, and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be
Feel free to ask further questions!
