If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper
Answer: We are given there are 49 cars
Also these 49 cars are in a line stretched 528 feet.
Now the average length of the car is:
Average length = 
=
Therefore, the average length of car is 10.78 feet
The ratio of Isabella’s money to Shane’s money is 3:11
Isabella has $33.
We can make a proportion to solve for how much money Shane has.
A proportion is two ratios that are set equal to each other.
Let’s call Shane’s money ‘S’
We get this proportion: 3/11 = 33/x
If we cross multiply we get:
(33) * (11) = (3) * (x)
Simplifying it, we get:
363 = (3) * (x)
Divide both sides by 3, we get:
x = 121
However, the question asks how much money they have together.
Isabella + Shane = Total
33 + 121 = $154
<span>They have $154 together.</span>
Answer:
The population reaches 7 million people in the year 2032.
Step-by-step explanation:
We have that
Using this model, find the year when the population reaches 7 million people.
This is x years after 2000, in which x is found when f(x) = 7. So
We have to following logarithm rule
So we apply log to both sides of the equality
2000 + 32.66 = 2032
The population reaches 7 million people in the year 2032.
Answer: I gave the evaluate answer and the differentiate w.r.t x answer. Sorry for caps.
Step-by-step explanation: EVALUATE x4n−3
DIFFERENTIATE W.R.T. X (4n−3)x4(n−1)
Length x width is the formula.
so 18 x 18 for 7.
22 x 24 for 8.
and 8 would probably be 5 x 5 to equal 20. so the length and width would be 5 and 5 because 20 is the area
