Answer:
Degree = 4
Step-by-step explanation:
For the given conditions:
n = 4
i and 5i are zeros
f(-2) = 145
For zeros, it means they are a quadratic factor of the expression
It means, we will have x = ± i and x = ± 5i
therefore, the given factors are (x - i)(x + i)(x - 5i)(x + 5i)
Hence, we have the function
given degree = 4
f(x) = a(x-i)(x+i)(x-5i)(x+5i)
f(x) = a(x² + 1)(x² + 25)
Hence, substituting -2 for x, we have
f(-2) = a(5)(29) = 145
Hence, a = 1
f(x) = x⁴ + 26x² + 25
Therefore, we can see that the given degree = 4
