Dada una ecuación de la forma
<h3>y = A sin(B(x + C)) + D</h3>
Tenemos que:
- la amplitud es A
- el periodo es 2π/B
- el desfase es C (a la izquierda es positivo)
- el desplazamiento vertical es D
Sabemos que:
f(x)=1+6Sen(2x+π/3)
Y podemos reescribirla como:
f(x)=6Sen(2(x+π/6))+1
Siendo:
- A = 6 → Amplitud
- T = 2π/B = 2π/2 = π → Período
- C = π/6 → Desfase
- El dominio de un a función trigonométrica es todo el conjunto de los números reales (x ∈ R ).
La imagen de una función trigonométrica de esta forma es:
y ∈ [-A+D,A+D]
y ∈ [-6+1, 6+1]
y ∈ [-5,7]
La gráfica se adjunta.
<h3>
Answer is -28</h3>
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Work Shown:
T(2) = 20 means the second term is 20
T(1) = 26 because we go backwards from what the rule says (subtract 6) to step back one term. Going forward, 26-6 = 20.
Since a = 26 is the first term and d = -6 is the common difference, the nth term is
T(n) = a + d*(n-1)
T(n) = 26 + (-6)(n-1)
T(n) = 26 - 6n + 6
T(n) = -6n + 32
Plugging n = 1 into the equation above leads to T(1) = 26. Using n = 2 leads to T(2) = 20.
Plug in n = 10 to find the tenth term
T(n) = -6n + 32
T(10) = -6(10) + 32
T(10) = -60+32
T(10) = -28
Step-by-step explanation:
If we use this formula then
X is 54 y is 45
54 + 45 = 11(54 + 45)
99 = 11(99)
99 = 1089
= 1089 - 99
= 990
If the slope is given then all is left is y-intercept which is equal to -3 which is also given in the question from the point (-4,-3), then your equation would be complete if you have these two so I think the answer is y=3/4x-3 and I’m really sorry if my answer is wrong but i tried my best and good luck!!
You have to use the Pythagorean theorem but there is a little twist here since a square has has equal sides. So:
x^2+x^2=8
2x^2=8
2/2x^2=8/2
x^2=4
√x^2=√4
x=2
The side of the square is 2.
So now the area of a square is:
Side×Side
2×2=4
The area of the square is 4 centimetres
