Where is 11/3 on a number line between 2 and 4

1 answer:

7 0

Hiii! To work it out, you would have to do 11 ÷ 3. Which would equal 3.6 (Recurring). If it's to one decimal place, it would be 4 if not, it would just be 3.6 ^^

Hope it helps!! Good luck~

You might be interested in

Express 3+4x-x^2 in the form y=p-(q-x)^2

BARSIC [14]

This is my way of doing it...
Rearrange the equation to -x^2+4x+3
Then -(x^2 - 4x) + 3
-[(x-2)^2 - 4] +3
-[(x-2)^2] +4+3
-(x-2)^2 + 7

final answer : y=7-(x-2)^2

5 0

3 years ago

Read 2 more answers

Arrange the steps in the correct order to prove the theorem "If A and B are sets, A is uncountable, and A âŠ† B, then B is uncou

Andre45 [30]

Answer:

Step-by-step explanation:

We are to rank the options given in the question to correctly prove the theorem that: "If A & B are set, and A is a subset of B"

To arrange the steps in the correct order, we have:

(a) Assume that B is countable

(b) The elements of B can be listed as b1, b2, b3

(c) Since A is a subset of B, taking the subsequence of {bn} that contains the terms that are in A gives a listing of the elements of A.

(d) Therefore A is countable, contradicting the hypothesis.

(e) Thus B is not countable

4 0

3 years ago

Find angle B. What is angle B.

julsineya [31]

Answer:

B=45 Degrees

Step-by-step explanation:

You can use law of sines to answer. Law of Sines states that $\frac{sin(a)}{A} =\frac{sin(b)}{B}$ . That means that $\frac{sin(60)}{4\sqrt{6} }=\frac{sin(b)}{8}$ . Multiplying 8 to both sides gives us $\frac{8sin(60)}{4\sqrt{6} }=sin(b)$ . By using inverse of sin, we get $b = sin^{-1} (\frac{8sin(60)}{4\sqrt{6} } )$ . Plugging that into a calculator gives us b=45 degrees.