To determine the area of a triangle, we calculate one half of the product of the base and the height of the triangle so we need data on its base and its height. We are given the following:
Hypotenuse = 7 + base = 14 + height
Perimeter = 84 inches
The perimeter of the triangle is equal to the sum of the three sides of the triangle which are the height, base and hypotenuse. So,
Perimeter = height + base + hypotenuse = 84
We let x = height and y = base. We calculate area as follows:
84 = x + y + (7 + y)
77 = x + 2y
x = 77 -2y
Hypotenuse is related to the other sides by the Pythagorean theorem.
Hypotenuse^2 = (x^2 + y^2)
(14 + x)^2 = x^2 + y^2
(14 + (77-2y))^2 = (77-2y)^2 + y^2
(91-2y)^2 = (77-2y)^2 + y^2
Solving for y and x
y = 28
x = 21
Area = (28)(21) / 2 = 294 square inches
2.07
2 + .07
Two and Seven Hundredths
Answer: 5
Step-by-step explanation: itswhere the 2 lines meet at the X
Answer:
x=4
Step-by-step explanation:
AB + BC = AC
AB= 6x, BC= x-5, AC= 23
Substituting what we know
6x + x-5 = 23
Combine like terms
7x -5 = 23
Add 5 to each side
7x-5+5 =23+5
7x = 28
Divide each side by 7
7x/7 = 28/7
x=4
Which question do you need answered or both?
