Question

If p(x)=2x^2 -4 and q(x)=x-3, what is (p*q)(x)

Answer 1

Answer:

2x^3 - 6x^2 - 4x + 12.

Step-by-step explanation:

(p*q) (x)  = (2x^2 - 4)(x - 3)

= 2x^3 - 6x^2 - 4x + 12.

Answer 2

For this case we have the following functions:

$p (x) = 2x ^ 2-4\\q (x) = x-3$

We must find $(p * q) (x).$ For definition, we have to:

$(p * q) (x) = p (x) * q (x)$

So:

$(p * q) (x) = (2x ^ 2-4) (x-3)$

We apply distributive property:

$(p * q) (x) = 2x ^ 3-6x ^ 2-4x + 12$

Answer:

$(p * q) (x) = 2x ^ 3-6x ^ 2-4x + 12$