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tiny-mole [99]
3 years ago
15

If p(x)=2x^2 -4 and q(x)=x-3, what is (p*q)(x)

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
4 0

Answer:

2x^3 - 6x^2 - 4x + 12.

Step-by-step explanation:

(p*q) (x)  = (2x^2 - 4)(x - 3)

= 2x^3 - 6x^2 - 4x + 12.

il63 [147K]3 years ago
3 0

For this case we have the following functions:

p (x) = 2x ^ 2-4\\q (x) = x-3

We must find (p * q) (x). For definition, we have to:

(p * q) (x) = p (x) * q (x)

So:

(p * q) (x) = (2x ^ 2-4) (x-3)

We apply distributive property:

(p * q) (x) = 2x ^ 3-6x ^ 2-4x + 12

Answer:

(p * q) (x) = 2x ^ 3-6x ^ 2-4x + 12

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Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

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To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

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\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

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