Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
The substance that has a mass of 148g and a volume of 40cm³ is 3.7g/cm³
In order to get the substance that has a mass of 148g and a volume of 40cm³, we need to first get the density of the substance.
Density is the ratio of mass per unit volume of a substance
Density = Mass/Volume
Given the following:
Mass = 148g
Volume = 40cm³
Density = 148/40
Density = 3.7g/cm³
Hence the density of the substance is 3.7g/cm³
Learn more here: brainly.com/question/17780219
Step-by-step explanation:
6m+7n+5m-3n
First you rearrange the terms
6m+5m+7n-3n
Then you combine like terms
11m+4n
And there you have it
Hope it helps!
P-1 is a factor.
∴p=1 is one of the root of p⁴ + p² + p -k
f(p) = p⁴ + p² + p - k
∴ f(1) = 1⁴ + 1 ² + 1 - k = 0
∴ k = 3
