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Alex787 [66]
3 years ago
8

What is the value of x? 40,000 mg = 10x g. A.400 B.40 C.4 or D 0.4

Mathematics
2 answers:
xeze [42]3 years ago
8 0
There are 1000mg in 1g, so 40,000mg = 40g
40g = 10x
x = C. 4g
MissTica3 years ago
3 0
I hope this helps you

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What must be true about the average rate of change between any two points on the graph of an increasing function?
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Shannon pours 4 different liquid ingredients into a bowl. The sum of the liquid ingredients is 8.53 liters. Two of her measureme
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4 0
3 years ago
A firm has the marginal-demand function where D(x)=-1400x÷√25-x² is the number of units sold at x dollars per unit. Find the dem
borishaifa [10]

The equation of the demand function is D(x) = 1400√(25-x²) + 11400

<h3>How to determine the demand function?</h3>

From the question, we have the following parameters that can be used in our computation:

Marginal demand function, D'(x) = -1400x÷√25-x²

Also, we have

D = 17000, when the value of x = 3

To start with, we need to integrate the marginal demand function, D'(x)

So, we have the following representation

D(x) = 1400√(25-x²) + C

Recall that

D = 17000 at x = 3

So, we have

17000 = 1400√(25-3²) + C

Evaluate

17000 = 5600 + C

Solve for C

C = 17000 - 5600

So, we have

C = 11400

Substitute C = 11400 in D(x) = 1400√(25-x²) + C

D(x) = 1400√(25-x²) + 11400

Hence, the function is D(x) = 1400√(25-x²) + 11400

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3 0
1 year ago
Help ASAP!
Tema [17]

Answer:

B

Step-by-step explanation:

\boxed{area \: of \: sector =  \frac{1}{2} {r}^{2} θ }

Radius= diameter ÷2

r= 32 ÷2

r= 16

\frac{1}{2}  {r}^{2} θ =  \frac{512\pi}{3}

Substitute r= 16,

\frac{1}{2} ( {16}^{2} )(θ) =  \frac{512\pi}{3}

128 \: θ =  \frac{512\pi}{3}  \\ θ =  \frac{512\pi}{3}  \div 128 \\ θ =  \frac{512\pi}{384}

Divide the denominator and numerator by 128:

θ =  \frac{4\pi}{3}

Thus, the answer is B.

3 0
3 years ago
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