1. Rob recently refinanced his monthly student loan

-3(5)^2-(-2)(-8) simplify

avanturin [10]

To do this, we're going to use the order of operations (PEMDAS):

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

First let's do parentheses, there isn't anythig in parentheses we need to simplify, so we can skip this step.

Next let's look for exponents. I see we have a $5^2$ so let's replace that with $5^2=25$ :

$-3(25)-(-2)(-8)$

Now let's look for multiplcation. We know that things that are right next to eachother in parentheses represent multiplcation, so let's simply this more:

$-3(25)=-75$

$(-2)(-8)=16$

$-75-16$

And now we're left with a simple problem we know how to solve.

Answer: $-91$

Hope this helps!

3 0

3 years ago

Determine the value of a if one solution to the quadratic equation is x equals 5 + 3/2 I

Sindrei [870]

The value of a is $\frac{-9}{4}$

Step-by-step explanation:

1. Determine the other solution of x

If one value is 5 + $\frac{3}{2}$ then the other value is 5 - $\frac{3}{2}$

2. Use reverse technique to find the equation

(5 + $\frac{3}{2}$ ) (5 - $\frac{3}{2}$ ) = 0

25 - $\frac{-15}{2}$ + $\frac{15}{2}$ - $\frac{9x^{2} }{4}$ = 0

- $\frac{9x^{2} }{4}$ + 25 = 0

3. The equation is - $\frac{9x^{2} }{4}$ + 25 = 0

4. Find the value of a

a is the number with the variable $x^{2}$ therefore it is - $\frac{9}{4}$

Keyword: quadratic equation, solution

Learn more about quadratic equation at

#LearnwithBrainly

8 0

3 years ago

When calculating the effective rate of a loan, which statement or statements must be true if n is greater than 1? I. The length

Fed [463]

When calculating the loan's effective rate, the most accurate statement is that the effective rate will exceed the nominal rate.

<h3>Effective Annual Rate:</h3>

The interest rate for the entire year is known as the effective annual rate (EAR). Interest charges are incurred when a company uses debt or capital leases to fund its operations.

Interest is reported on the income statement, but it can also be generated on an investment or paid on a loan over time due to compounding interest.

It is frequently larger than the marginal rate and is used to compare various financial products with different compounding periods, such as weekly, monthly, and yearly.

The effective yearly interest rate rises over time as the number of compounding periods increases.

Therefore, the correct option is A.

Learn more about the loans here:

brainly.com/question/2405320

8 0

3 years ago

Read 2 more answers

Shen borrowed $8000 at a rate of 12%, compounded semiannually. Assuming he makes no payments, how much will he owe after 7 years

Alexandra [31]

Answer:

$18,087.23

Step-by-step explanation:

The future worth of the loan in 7 years compounded semiannually is computed as shown below using the future value formula adjusted for semiannual compounding:

FV=PV*(1+r/2)^n*2

FV is the worth of the loan in 7 years which is unknown

PV is the actual amount of loan which is $8,000

r is the rate of interest of 12%

n is the number of years of the loan which is 7 years

the 2 is to show that interest is computed twice a year

FV=8000*(1+12%/2)^7*2

FV=8000*(1+6%)^14

FV=8000*1.06^14=$18,087.23

4 0

3 years ago

Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg

Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) Optimal solution: 40.000 units of R and 10.000 of PC = $17.000

c) Slack variables: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) Binding Constaints:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.

3 0

3 years ago