Answer:
A polynomial function that meet the conditions is x³ - 8x² + 5x + 14 = 0
Step-by-step explanation:
Hi there!
Let´s start writting a generic factored function. In this case, the function has 3 zeros so that the factored form will have 3 terms:
(x + a)(x + b)(x + c) = 0
For this expression to be 0, either (x+a) = 0 or (x+b) = 0 or (x+c) = 0
Then:
x + a = 0 ⇒ x = -a
x + b = 0 ⇒ x = -b
x + c = 0 ⇒ x = -c
Then, the values "a", "b" and "c" are equal to the zeros of the function but with opposite sign. Then, in our case:
a = 1
b = -2
c = -7
Then, the polynomial fuction will be:
(x + 1)(x - 2)(x - 7) = 0
Apply distributive property:
(x² - 2x + x -2)(x -7) = 0
(x² - x - 2)(x - 7)
x³ - x² - 2x - 7x² + 7x + 14 = 0
x³ - 8x² + 5x + 14 = 0
Then, a polynomial function that meets the conditions is:
x³ - 8x² + 5x + 14 = 0
Have a nice day!
