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True [87]
3 years ago
9

Addison and wyatt whine a lot For every 3 minutes Wyatt whines, Addison whines 2 minutes. If they whine 45 minutes all together,

for how long did Addison whine?
Mathematics
1 answer:
dangina [55]3 years ago
8 0

To solve this problem you must apply the proccedure shown below:

1. You have that Addison whines 2 minutes for every 3 minutes Wyatt whines. And they whine a total of 45 minutes. Therefore, you can make the following system of equations, where x is the minutes that Wyatt whines and y the minutes that Addison whines:

\left \{ {{x=\frac{3}{2}y } \atop {x+y=45}} \right.

2. You can solve it by the Method of subtitution:

x+y=45

\frac{3}{2}y+y=45

\frac{5}{2}y=45

y=18

3. Now, calculate x

x+18=45

x=27

Therefore, the answer is: Addison whined for 18 minutes.

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