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pentagon [3]
3 years ago
12

At the beginning of the week Fayez writes drown the mileage of his limousine - 2529 At the end of the week the mileage is 2834,

Fayez knows he used 75.2 litres of petrol during the week. The handbook states that the limo uses 1 gallon of petrol for every 20 miles. Fayez wants to know if his limousine used 1 gallon of petrol for every 20 miles this week 1 gallon = 4.54 litres Did his limo use 1 gallon of petrol for every 20 miles that week? Explain answer in full Please help!!
Mathematics
1 answer:
Alexandra [31]3 years ago
4 0
2834 - 2529 = 305 miles traveled
75.2 / 4.64 = 16.4 gallons used
305 / 16.4 = 18.5 miles per gallon
The limo did not use 1 gallon every 20 miles.
The limo used 1 gallon every 18.5 miles
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Answer:

D) 11/12

Step-by-step explanation:

From 1 to 12, 6 numbers are odd (1, 3, 5, 7, 9, and 11).

7 numbers are non-prime (1, 4, 6, 8, 9, 10, and 12).

2 numbers are both odd and non-prime (1 and 9).

Therefore, the probability is:

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3 years ago
g Suppose the population 10-year cumulative incidence of prostate cancer among 70-year old men is 0.06. Further, suppose 260 men
Rainbow [258]

Answer:

There is not enough statistical evidence to conclude that the cumulative incidence of prostrate cancer among 50-year old men differs from that of 70-year old men

Step-by-step explanation:

The population 10 year cumulative incidence of prostrate cancer among 70 year old men, p = 0.06

The number of 50 year old men in the sample, n = 260 men

The number of the sampled men that developed prostrate cancer = 13 men

The significance level, α = 0.05

Let the null hypothesis, H₀: \hat{p} = p

The alternative hypothesis, Hₐ: \hat{p} ≠ p

The standard score, z_{\alpha /2} = 1.96

The test statistic, 'z', is given as follows;

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p \cdot q}{n}}}

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q = 1 - p = 1 - 0.06 = 0.94

Therefore,  \ z=\dfrac{0.05-0.06}{\sqrt{\dfrac{0.06 \times 0.94}{260}}} = \dfrac{\sqrt{9165} }{141} \approx -0.68

From the z-table, we find the p-value as follows;

P(z ≈ -0.68) = 0.24825

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2 years ago
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3 years ago
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What is the question
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