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worty [1.4K]
3 years ago
8

The sum of y and 20 is less than 37

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0
Y + 20 < 37

y < 17 the answer to the question
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What is P(2 or divisor of 9)?<br> please explain!
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The probability that a divisor of 2 or 9 is chosen when the spinner is spun once is 2/3.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

P(2 or divisor of 9) = section that has a divisor of 2/ total number of sections + section that has a divisor of 2/ total number of sections

1/3 + 1/ 3 = 2/3

To learn more about probability, please check: brainly.com/question/13234031

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A circle is centered at J(3, 3) and has a radius of 12.
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Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

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