All categories

3 years ago

Can someone help answer the first two?

Mathematics

1 answer:

Murljashka [212]3 years ago

5 0

Answer:

below given!

Step-by-step explanation:

1) mean = (7.4 + 5.8 + 7.3 + 7 + 8.9 + 9.4 + 8.3 + 9.3 + 6.9 + 7.5 + 9 + 5.8 + 5.5 + 8.6 + 9.3 +3.8) / 16

mean = 7.47

You might be interested in

UPS charges $6.00 for the first pound, $1.00 for the second pound, and $0.15 for each additional pound. FedEx charges $4.00 for

Pavlova-9 [17]

Answer:

12 pounds

Step-by-step explanation:

We we need to write equations to represent the situation in this problem.

x=weight of package

UPS cost=6+1+0.15(x-2)

UPS cost=6+1+0.15x-0.3

UPS cost=6.7+0.15x

FedEx cost=4+2+.25(x-2)

FedEx cost=4+2+0.25x-0.5

FedEx cost=5.5+0.25x

Next, we can set the two equations equal to each other to solve for x.

6.7+0.15x=5.5+0.25x

6.7+0.15x-5.5=5.5+0.25x-5.5

1.2+0.15x-0.15x=0.25x-0.15x

1.2/0.1=0.1x/0.1

x=12

It takes 12 pounds for the UPS and FedEx packages to cost the same amount to ship.

8 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$