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Tanzania [10]
3 years ago
9

For the diwali mela organised by a ladies club,Sarita sold 325 on the first day and 496 samosa on the second day . How many samo

sas were sold in all​
Mathematics
2 answers:
iragen [17]3 years ago
3 0

Answer:

821

Step-by-step explanation:

First day: 325

Second day: 496

It’s asking how many samosas were sold in all so we have to add the 325 samosas from the first day to the 496 samosas on the second day.

325

+ 496

—————

821

alexandr402 [8]3 years ago
3 0

Answer:

The answer is 821.

Step-by-step explanation:

By adding 325 and 496 we have 821.

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Answer:

6/9=2/3

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

a 96:100 = 24 : x

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Three out of five students said math was their favorite subject. What percentage of students preferred math?
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What two numbers multiply to 54 and add up to 7
k0ka [10]
Xy = 54
x + y = 7

xy = 54
\frac{xy}{x} = \frac{54}{x}
y = \frac{54}{x}

x + y = 7
x + \frac{54}{x} = 7
\frac{x^{2}}{x} + \frac{54}{x} = 7
\frac{x^{2} + 54}{x} = 7
x^{2} + 54 = 7x
x^{2} - 7x + 54 = 0
x = \frac{-(-7) \± \sqrt{(-7)^{2} - 4(1)(54)}}{2(1)}
x = \frac{7 \± \sqrt{49 - 216}}{2}
x = \frac{7 \± \sqrt{-167}}{2}
x = \frac{7 \± i\sqrt{167}}{2}
x = \frac{7 \± 12.9i}{2}
x = 3.5 \± 6.45i
x = 3.5 + 6.45i    or    3.5 - 6.45i

                  x + y = 7
   3.5 + 6.45i + y = 7
- (3.5 + 6.45i)       - (3.5 + 6.45i)
                        y = 3.5 - 6.45i
                  (x, y) = (3.5 + 6.45i, (3.5 - 6.45i)

                          or

                  x + y = 7
   3.5 - 6.45i + y = 7
- (3.5 - 6.45i)     - (3.5 - 6.45i)
                       y = 3.5 + 6.45i
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5 0
3 years ago
If natalie and her friends decide to rent 4 lanes at reguler cost for a party ten people need to rent shoes and 4 people are mem
taurus [48]

The question is missing a tabular data. So, it is attached below.

Answer:

The total cost for the party is $74.50.

Step-by-step explanation:

Given:

Lanes rented at regular cost = 4

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Cost of 1 shoe rental for members = $2.95

Since, lanes are rented at regular cost, we use unit rate at regular cost

So, cost of 4 lanes rented = 4\times 9.75= \$ 39

Now, out of 10 people who rented shoes, 4 are members. So, the number of non-members is given as:

Non members who rented shoes = 10 - 4 = 6

So, 4 members and 6 nonmembers rented shoes.

So, cost of 6 non members renting shoes = 6\times 3.95=\$ 23.70

Cost of 4 members renting shoes = 4\times 2.95=\$ 11.80

Total cost for the party is the sum of all the costs. This gives,

= 39 + 11.80 + 23.70

= 50.80 + 23.70

= $74.50

Therefore, the total cost for the party is $74.50.

5 0
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