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N76 [4]
3 years ago
10

El suplemento del angulo T es 4 veces la medida del angulo T​

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:;0

Step-by-step explanation:

Lol

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In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
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Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

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Step-by-step explanation:

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I would like to request help for this problem. I am having trouble understand how to solve the problem.
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