Answer:
The new radius r' should be 1.1 times the original planned radius ( rp ).
Step-by-step explanation:
Solution:-
- We will assume the geometry of the pond is modeled as a cylinder with base modeled as a circle with radius ( r ) and the planned height of the ( hp = 6 feet ).
- The volume V of a cylindrical pond is given by:
V = π*r^2*h
- Talisa had planned a depth hp = 6 feet, The planned volume with planned radius ( rp ) was:
Vp = π*rp^2*6
- However, she hit a rock at h' = 5 feet, So what change must he make to the radius of the pond such that she achieves the planned volume of the pond.
V = π*r'^2*h'
Where, r' is the new radius of the pond:
Vp = V
π*rp^2*6 = π*r'^2*5
( r' / rp )^2 = 6 / 5
r' / rp = √6 / 5
r' / rp = 1.09544
r' = 1.1*rp
- The new radius r' should be 1.1 times the original planned radius ( rp ).
1/3 x 1/4 is (1x1) / (4x3) = 1/12 which is in its lowest terms
The area is 25, because the length and width are both 5.
5× 5 = 25 (area)
5 + 5 + 5 + 5 = 20 (perimeter)
You're welcome :)
formula of a slope of a line when 2 points are given:
delta y/ delta x= slope -> y2-y1 / x2-x1= slope so:
8-4 / -1 +3
= 4/ 2
= 1/2