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finlep [7]
3 years ago
11

B. He lays the short edge of the paper along the short edge of the frame several times

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0
If you mean standard 8.5x11 paper then 3 papers wide would make it 25.5in or 2.13 feet.
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for a certain company, the cost function for producing x items is C(x)=40x+150 and the revenue function for selling x items is R
Mademuasel [1]

Answer  :

Step-by-step explaation:

c(80) =40x80 +150 =3350  üretim için 80  parçanın maliyeti

satış için ise : R(80) 0.5(80-110)^2+6,050 =  456

3350-456=2983.95 kar ederler  

5 0
2 years ago
If AB=6x-7 and BC=5x-3 find AC
luda_lava [24]

Answer:

AC= AB+BC

= 6x-7+ 5x-3

= 11x-10

4 0
3 years ago
How many times dose 12 go into 41
jonny [76]

Answer:

3.42

Step-by-step explanation:

41/12 is 3.42

3 0
2 years ago
Read 2 more answers
The graph of the even function F(X) Has 5 x-intercepts if (6,0) is the one of the intercepts what set of points can be the other
alex41 [277]

f(x) being even means


f(x) = f(-x)


So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.


Given zero x=6 we know x=-6 is also a zero.


So we know three zeros, and know the other two zeros are a positive and negative pair.


The only choice with (-6,0) and (0,0) is A.


Choice A



3 0
2 years ago
Read 2 more answers
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0
2 years ago
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