Answer:
meters per seconds squared
Step-by-step explanation:
seconds squared cancel out and you're leftvwith just meters when
meters/seconds squared is multiplied with the seconds squared in t^2
g means gravity and
gravity is 9.8 meters per second squared
nasa
Answer:
x > 17
Step-by-step explanation:
Add 8 to both sides:
6x - 8 > 4x + 26
6x > 4x + 34
Subtract 4x from both sides:
2x > 34
Divide each side by 2:
x > 17
So, the solution is x > 17
Answer:

Step-by-step explanation:
The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!
<u>Center of the circle:</u>
- The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).
Using the midpoint formula we'll get:



This is the center coordinate of our circle.
<u>Radius: </u>
The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)
We can use the distance formula:





<u>Equation of the circle: </u>
The equation is written as:

here, (a,b) are the center points of the circle
in our case this is 
and r = 1


This is the equation of the circle!
6×11=66
11+66=77
so the first number is 11 and the second is 66. together their sum is 77.
9/3 is already made a fraction.
Why?
Because it is not a whole numer.
Well, this improper fraction can be simplified.
<u>9 </u> ÷ 3<u>
</u>3 ÷ 3
= 1.
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