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Oksanka [162]
3 years ago
12

True or False - One advantage of polar equations is that you can use a polar function to describe a graph whose equation in rect

angular coordinates would not be considered a function.
Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

The answer is TRUE.

Step-by-step explanation:

One advantage of polar equations is that you can use a polar function to describe a graph whose equation in rectangular coordinates would not be considered a function - this is true.

Polar equations are algebraic curves expressed in polar coordinates. For polar equations, we define r as a function of θ, where r represents the distance from the pole to a point on a curve, and θ represents the counterclockwise angle made by a point on a curve, the pole, and the positive x-axis.

tresset_1 [31]3 years ago
4 0
Yup! Consider the circle:

r=cnt, for any angle. Impossible with (x,y), because for a given x, you need to y values. For a circle of radius 1, centered at the origin, y = +sqrt( 1-x^2) and y = -sqrt(1-x^2)

Also the spiral, etc ... Any hta has for one x value, two or more y values.
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M is the midpoint of PQ. <br> PM = 5x + 8 and PQ = 76, find x.<br> (2 Points)<br> Enter your answer
BabaBlast [244]

Answer: x=6

Step-by-step explanation:

Just think about how the problem is half

4 0
3 years ago
A bag contains 4 yellow balls, 5 red balls, and 6 blue balls.
seraphim [82]
A = 4/15

B = 6/15

Explabanation:
The formula used is Amount requested/Total amount
6 0
2 years ago
1.5=0.5/x<br><br> (the 0.5/x is a fraction )Please answerrrrr!
mr Goodwill [35]

Answer: x=0.3 (continuous)


Step-by-step explanation:


8 0
3 years ago
Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky
cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of stars in a given volume of space.

X\sim \text{Poisson}\ (\lambda=1)

The probability mass function of <em>X</em> is:

p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

P(X\geq 3)=1-P(X

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in <em>t</em> cubic light years there will be, [<em>t</em> × (1/16)] stars.

7 0
3 years ago
Jill has $9.96 in nickels, pennies, and dollar bills in her bank. If she has 12 more pennies than nickels and 5 less dollar bill
9966 [12]
Number of pennies:P
Number of nickels:N
Number of dollar bills:D
P=N+12
N=D+5
1P+5N+100D=996
^given
Therefore
P=(D+5)+12
P=D+17
Plug back into main equation
(D+17)+5(D+5)+100D=996
Combine like terms
106D+42=996
106D=954
D=954/106=9

9 Dollar bills

N=D+5
N=(9)+5=14

14 Nickels

P=N+12
P=(14)+12=26

26 Pennies

26*1+14*5+9*100=996

Final answer:
9 Dollars
14 Nickels
26 Pennies

3 0
3 years ago
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