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o-na [289]
4 years ago
7

If f(x) = 3x 7, what is f(-2)?

Mathematics
1 answer:
xxMikexx [17]4 years ago
6 0
-6×7
-42
It's answer is -42
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The correct answers to questions
gayaneshka [121]
I can’t help you unless I can see the answers for the questions
6 0
3 years ago
Write an equation in slope-intercept form of the line through point P(8,2) with slope 4
nata0808 [166]

Hello!

Firstly, we need to know what the slope-intercept form is. Slope-intercept form is y = mx + b. In this equation, m is the slope and b is the y-intercept.

Our goal here is to find the y-intercept. To find b, we will substitute the slope and the given ordered pair into the slope-intercept equation and solve algebraically.

y = mx + b (substitute the slope and point P)

2 = 2(8) + b (multiply)

2 = 16 + b (subtract 16 from both sides)

b = -14

Therefore, the equation is y = 2x - 14.

4 0
4 years ago
Evaluate the expression when c=-6 <br> c^2+7c-5
xz_007 [3.2K]
 -5.16666667
first you have to subtract c from both sides.
0=-6^2+6c-5
0=36+6c-5
0=31+6c
then subtract 31 from both sides.
-31=6c
then -31 divided by 6
8 0
4 years ago
Find the distance between the points X and Y on the coordinate plane.
irina [24]
The answer is 9 (D)

:)
3 0
3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
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