so leg A would be 60
leg B would be 85
using this we are able to determine the HYP to be 104.04
so sine = opp/HYP
leg A is the opp in this case
sin(theta) = 60/104.04
sin(theta) = 0.57670126874
when we round to the hundredths place we get 0.58
:dab:
Answer: c = -7
Step-by-step explanation:
-4 + c = -11
c = -7
Answer:
uhm, i need this answer also
Step-by-step explanation:
did you ever get the answer ? if so could you be kind enough to give it to me pleasee
2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j
Answer:
x = 24.1
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan 15 = x/90
90 tan 15 =x
x=24.11542
To the nearest tenth
x = 24.1
