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kakasveta [241]
3 years ago
11

If no digit may be used more than once, how many 5-digit numbers can be formed using only the digits 3, 8, 1, 2, 5, and 7?

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

The number of permutations of m(0\leq m\leq n) objects from n objects is

P(m,n)=\frac{n!}{(n-m)!}

Here 5 digits are chosen from 6 digits without replacement (order important).

The number of 5 digit numbers that can be formed is

\frac{6!}{(6-5)!} =6!=720

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