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Vikki [24]
3 years ago
8

Solve The Problems

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0
1. C
2. B
3. B
4. D
i think 4 might be wrong tho.
spayn [35]3 years ago
4 0
X - 7 > 10
x > 10 + 7
x > 17

3x < = 21
x < = 21/3
x < = 7

5a - 2 < 18
5a < 18 + 2
5a < 20
a < 20/5
a < 4

2t + 8 > = -4 (t + 1)
2t + 8 > = -4t - 4
2t + 4t > = -4 - 8
6t > = - 12
t > = -12/6
t > = -2




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A coin bank contains only quarters and dimes. The total value of the coins in the bank is $8.80. If the dimes were quarters and
masha68 [24]

Answer:

  • 18 dimes

Step-by-step explanation:

Let the number of dimes be d and quarters be q

<u>The value is $8.80 = 880¢, so:</u>

  • 10d + 25q = 880 ⇒ 2d + 5q = 176

<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>

  • 25d + 10q = 730 ⇒ 5d + 2q = 146

<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>

  • 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
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  • -21d = -378
  • d = -378/-21
  • d = 18
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3 years ago
Find the values of x and y in the diagram below.<br> 86°<br> (4x - 7)°<br> (7y - 1)<br> (9x + 4)
Aneli [31]

The value of x in the diagram is 15° and the value of y is 6°

Please find attached the diagram used in answering this question

The figure given is a triangle. A triangle is a polygon with three sides. The sum of angles in a triangle is 180 degrees

The first step is to determine the value of x.

The value of x can be determined using the exterior angle.

The sum of the two interior opposite angles in a triangle is equal to the external angle

(4x - 7)° + 86° = (9x + 4)°

Combine similar terms

9x - 4x = 86 - 7 - 4

5x = 75

x = 15°

To determine the value of y, first substitute for the value of x in the angle (4x - 7)°

(4x - 7)° = (4x15) - 7 = 53°

The sum of angles in a triangle add up to 180°

53° + 86 + (7y - 1) = 180°

add like terms

138 + 7y = 180

7y = 42

y = 6°

To learn more, please check: brainly.com/question/23688688?referrer=searchResults

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