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Anvisha [2.4K]
3 years ago
9

Chloe needed to get her computer fixed. She took it to the repair store. The technician

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

he took $55.8for 1hr

Step-by-step explanation:

it's because we should devid eit for calculation for minute

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HELP ASAP (40 POINTS)
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PLEASE HELP ILL GIVE BRAINLY
NISA [10]

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40.2

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Twenty-five sixth-grade students were asked to estimate how many hours a week they spend talking on the phone. This dot plot rep
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where is the dot plot??

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7 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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5 0
2 years ago
Two trains leave stations 288 miles apart at the same time and travel towards each other. One train travels at 95 miles per hour
erma4kov [3.2K]
95x=85x+288
You could add 288 to any side, it just shows that they're 288 miles apart.
Let's subtract 85x from both sides.
10x=288
28.8=x
It'll take 28.8 hours for the trains to meet. Let's make sure.
28.8×95
2,736
28.8×85
2,448
2,736-2,448
288
So, they'll meet up after 28.8 miles.

5 0
3 years ago
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