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Zolol [24]
3 years ago
8

Ebonae fish tank holds 40 gallons.how many quarts does the fish tank hold?

Mathematics
1 answer:
Rudik [331]3 years ago
5 0
The fish tank that ebonae can hold up to 160 quarts of water

4x40=160
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Which of the following is a unit rate?
Snezhnost [94]

Answer:

The third option (foot/1 hour)

Step-by-step explanation:

4 0
2 years ago
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Is 5/8 more than 11/20
alexdok [17]
5/8 is more than 11/20

If we find the lower common multiple of the denominators which is 160 then we can multiply the top numerators by the opposite denominators

5x20=100
11x8=88

We now have
\frac{100}{160}  and  \frac{88}{160}

The one on the left is simplified to 5/8 and the right is simplified to 11/20

5 0
3 years ago
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The price of a new car was $12 500 It is reduced to £11 625 Work out the percentage reduction
cricket20 [7]
Answer:

12,500-11,625=875

875/12,500=7/100

7/100*100=7

The percentage reduction is 7%

P.S * represents multiplication
4 0
2 years ago
Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

8 0
3 years ago
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Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
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