9514 1404 393
Answer:
yes
Step-by-step explanation:
If GH║FE, then ∆DEF ~ ∆DHG.
In similar triangles, corresponding sides have the same ratios.
The ratios of corresponding sides are ...
DG/DF = DH/DE
DG/(DG + GF) = 18/(18+36)
(1/2GF)/((1/2GF +GF) = 1/3
(1/2)/(3/2) = 1/3
1/3 = 1/3
Corresponding sides are proportional. Angle D is congruent to itself, so ∆DEF ~ ∆DHG by the SAS similarity postulate. Angles DGH and DFE are therefore congruent and GH║FE.
Answer:
0
Step-by-step explanation:
please look at the picture that I attached and try to understand it
9514 1404 393
Answer:
3.65% monthly
Step-by-step explanation:
The same amount is invested for the same period in all accounts, so we only need to determine the effective annual rate in order to compare the accounts.
For compounding annual rate r n times per year, the effective annual rate is ...
(1 +r/n)^n -1
For the same rate r, larger values of n cause effective rate to be higher. As a consequence, we know that 3.65% compounded quarterly will not have as great a yield as 3.65% compounded monthly. The effective rate for the monthly compounding is ...
(1 +0.0365/12)^12 -1 = 3.712%
The effective rate for continuous compounding is ...
e^r -1
For a continuously compounded rate of 3.6%, the effective annual rate is ...
e^0.036 -1 = 3.666%
This tells us the best yield is in the account bearing 3.65% compounded monthly.
_____
If i is the effective annual rate of interest as computed by the methods above, then the 10-year account balance will be ...
10000×(1 +i)^10
This is the formula used in the spreadsheet to calculate the balances shown.
Answer:
True.
Step-by-step explanation:
By definition of a mid point, it is located in the middle of two connected points. This means that the split is equal on both sides.
IF X is the midpoint of ZW, then ZX = XW.
~
Answer: Choice D
Explanation:
We have the two points (2,2) and (2,-2) which have a repeated x coordinate. This is not allowed if we wanted a function. A function must have any x input lead to exactly one and only one output (assuming the input is in the domain).