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kumpel [21]
3 years ago
10

Anyone wanna help me answer this? Help me out please

Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

(-1,5\frac{1}{2})

(0, 6)

(1, 6\frac{1}{2})

(2, 7)

Step-by-step explanation:

Just implement x and solve for y.

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Please help me solve? (m3n + 8)(m3n - 5) multiplying polynomial by polynomial
ruslelena [56]

The final result should be m^{6}n^{2}  - 3m^{3}n - 40.

In order to multiply any polynomials, use the pattern FOIL (which stands for first, outer, inner, last). You multiply what they ask you to at each step.

First - The first terms in both parenthesis.

m^{3}n * m^{3}n = m^{6}n^{2}

Outer - The terms on the outside of both parenthesis.

m^{3}n * -5 = -5m^{3}n

Inner - The terms on the inside of both parenthesis.

m^{3}n * 8 = 8m^{3}n

Last - the last numbers in each parenthesis.

8 * - 5 = - 40

Now we put all the answers together and simplify like terms,

m^{6}n^{2} + -5m^{3}n + 8m^{3}n - 40

m^{6}n^{2} - 3m^{3}n - 40

8 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height
Ilia_Sergeevich [38]

Answer:

\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}

From this point on, you have two possibilities, either you find each individual y_{f}, y_{0}, t_{f}, t_{0} and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

t_{f}-t_{0}=\Delta t

and we also know that:

t_{f}=t_{0}+\Delta t

in order to find the final position, we can substitute this final time into the function, so we get:

y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}

so we can rewrite our formula as:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}

y_{0} will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

y_{0}=29t-22t^{2}

y_{0}=29(1)-22(1)^{2}

y_{0}=7ft

we can substitute it into our average velocity equation:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}

and we also know that the initil time will always be 1, so we can substitute it as well.

\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}

so we can now simplify our formula by expanding the numerator:

\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}

\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}

we can now simplify this to:

\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}

Now we can factor Δt to get:

\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}

and simplify

\overline{v}=-15-22\Delta t

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s

\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s

\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s

\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s

5 0
3 years ago
What is the sum of 2/10 and 20/100
yawa3891 [41]
2 / 10 = 20 / 100.

So 2 /10 + 2 / 10 = 4 / 10.

Simplify that to 2 / 5.
7 0
3 years ago
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slava [35]
3.2 goes in the first and second blank, 8.7 is the final answer
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3 years ago
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The height of a baseball in feet x seconds after a batter hits it can be represented by the function f(x)=−2x2+10. How many feet
s344n2d4d5 [400]

Answer:

So, at 2 seconds the baseball reaches its maximum height and its maximum height is 69 feets.

Step-by-step explanation:

8 0
3 years ago
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