We use long division to divide
There is no x term in x^2 -1 so we put 0x
x + 1
----------------------------
x^2+0x-1 x^3+ x^2 + x+ 2
x^3+0x^2-x
-----------------------------(subtract the bottom from top)
x^2 +2x + 2
x^2 +0x - 1
--------------------------------(subtract the bottom from top)
2x + 3
-----------------------------------------
Quotient : x+1
Remainder : 2x+3
<h3>
Answer: B) Complex numbers</h3>
Complex numbers are always in the form a+bi with 'a' and 'b' as real numbers.
If b = 0 and 'a' is nonzero, then a+bi = a+0i = a which is strictly a real number
If a = 0 and b is nonzero, then a+bi = 0+bi = bi indicating that the number is now purely imaginary
Answer:
1.275
Step-by-step explanation:
Answer:
x = 6/5 or x = -2
Step-by-step explanation:
We need to solve:
|5x+2|=8
We know that |u|=a the u = a and u = -a
Now solving:
|5x+2|=8
5x +2 = 8 or 5x +2 = -8
5x = 8-2 or 5x = -8-2
5x = 6 or 5x = -10
x = 6/5 or x = -10/5
x = 6/5 or x = -2
So, x = 6/5 or x = -2
I'm assuming you mean (a-b)^2 : (a+b)^2
a^2 + b^2 cancel out leaving
-2ab versus +2ab
Therefore (a+b)^2 is +4ab greater.
