Answer:
y = - 16t² + 55.6t + 6
Step-by-step explanation:
Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football
So y = y₀ + vt - 1/2 × (32 ft/s²)t²
y = y₀ + vt - 16t² where y₀ = 6.5 ft
y = 6 + vt - 16t²
Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have
5 = 6.5 + v(3.5 s) - 16(3.5 s)²
5 = 6.5 + 3.5v - 196
collecting like terms, we have
5 - 6.5 + 196 = 3.5v
194.5 = 3.5v
v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s
So, substituting v into y, our quadratic model is
y = 6 + 55.6t - 16t²
re-arranging, we have
y = - 16t² + 55.6t + 6
Answer:
d
Step-by-step explanation:
Answer:
Option D. |10| + |-6|
Step-by-step explanation:
we know that
the formula to calculate the distance between two points is equal to
we have
(10,4) and (-6,4)
substitute
therefore
The expression that could help to find the distance is
Answer:
the answer would be B 36*27=27*36
Step-by-step explanation:
This is because the number placement changed with the numbers staying the same.
Hope this helps! :)
And have a great Friday!!
Answer:
and
Step-by-step explanation:
To solve the equation, 
, using the quadratic formula,
Recall: quadratic formula = 
Where,
a = 1
b = -14
c = 22
Plug in your values into the formula and solve:
And
