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WINSTONCH [101]
3 years ago
5

Graph the linear equation y=2

Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

(0,2)

Step-by-step explanation:

Basically, the x coordinate is non-existent, so it is a 0. The y is 2. So the coordinates are (0,2). The line you graph should be a horizontal line on the y-axis.

Sorry if my explanation didn't make sense but I'm positive my answer is correct.

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A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His
sergejj [24]

Answer:

y = - 16t² + 55.6t + 6

Step-by-step explanation:

Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football

So y = y₀ + vt - 1/2 × (32 ft/s²)t²

y = y₀ + vt - 16t² where y₀ = 6.5 ft

y = 6 + vt - 16t²

Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have

5 = 6.5 + v(3.5 s) - 16(3.5 s)²

5 = 6.5 + 3.5v - 196

collecting like terms, we have

5 - 6.5 + 196 = 3.5v

194.5 = 3.5v

v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s

So, substituting v into y, our quadratic model is

y = 6 + 55.6t - 16t²

re-arranging, we have

y = - 16t² + 55.6t + 6

6 0
3 years ago
What is the product for this question. Explain how if you can
Lyrx [107]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
Which expression could help you find the distance between (10,4) and (-6,4) ?
lina2011 [118]

Answer:

Option D. |10| + |-6|

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(10,4) and (-6,4)

substitute

d=\sqrt{(4-4)^{2}+(-6-10)^{2}}

d=\sqrt{(0)^{2}+(-16)^{2}}

d=16\ units

therefore

The expression that could help to find the distance is

|10| + |-6|=10+6=16\ units

4 0
3 years ago
Can someone pls help
NARA [144]

Answer:

the answer would be B 36*27=27*36

Step-by-step explanation:

This is because the number placement changed with the numbers staying the same.

Hope this helps! :)

And have a great Friday!!

7 0
3 years ago
Help with number 50 please. Thanks.
Blizzard [7]

Answer:

d = 7 + 3\sqrt{3} and

d = 7 - 3\sqrt{3}

Step-by-step explanation:

To solve the equation, d^2 - 14d - 22 = 0, using the quadratic formula,

Recall: quadratic formula = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}

Where,

a = 1

b = -14

c = 22

Plug in your values into the formula and solve:

\frac{-(-14) ± \sqrt{(-14)^2 - 4(1)(22)}}{2(1)}

\frac{14 ± \sqrt{196 - 88}}{2}

\frac{14 ± \sqrt{108}}{2}

d = \frac{14 + \sqrt{108}}{2}

d = \frac{14 + 6\sqrt{3}}{2}

d = (\frac{2(7 + 3\sqrt{3})}{2}

d = 7 + 3\sqrt{3}

And

d = \frac{14 - \sqrt{108}}{2}

d = \frac{14 - 6\sqrt{3}}{2}

d = (\frac{2(7 - 3\sqrt{3})}{2}

d = 7 - 3\sqrt{3}

4 0
3 years ago
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