Question

sam has a jar that contains 6 blue marbles and 5 violet marbles. he randomly draws one marble and then draws another marble .What is the probability of drawing two violet marbles without replacement

Answer 1

The probability of drawing a violet marble on the first draw is 5/11.
Having drawn violet on the first draw, there are now 4 violet marbles left and a total of 10 marbles. So, the probability of violet on the second draw is 4/10.
$P(2\ violet)=\frac{5}{11}\times \frac{4}{10}= \frac{2}{11}$