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Molodets [167]
3 years ago
12

What is the length of feet in 5 equal length of ribbon equaling 2 yards of ribbon

Mathematics
1 answer:
alisha [4.7K]3 years ago
3 0
Am presuming you are asking for the length of each ribbon in feet.

5 of them = 2 yards.

1 of them =  2/5 = 0.4 yards.

But note 3 feet make 1 yard.

Therefore:  0.4 yards = 0.4 * 3 feet =  1.2 feet.
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Write an algebraic expression that represent the sum of 8 and two-third of x?
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We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,

thus, the expression is

\frac{2}{3}x+8

3 0
1 year ago
-17=5s - 7<br> Can you help me?
julsineya [31]

Answer:

S=-2

Step-by-step explanation:

7 0
3 years ago
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What's the answer to this question
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Marcus is selling lemonade and peanuts. Each cup of lemonade cost $0.75, and each bag of peanuts costs $0.35. On Saturday, Marcu
andreev551 [17]
Marcus sold 8 cups of lemonade and 3 bags of peanuts. 0.75 times 8 equals $6.00. 0.35 times 3 equals $1.05. $6.00+ $1.05= $7.05. Your welcome dude

7 0
3 years ago
An airplane is flying overhead at a constant elevation of 405 ft. A person is viewing the plane from a position 3040 ft from the
Gnoma [55]

Answer:

δL/δt = 634,38 ft/s

Step-by-step explanation:

A right triangle is shaped by  ( y = distance between aircraft and ground which is constant and equal to  405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f   and the line between the aircraft and the person. Then we can use Pythagoras theorem and write

L ( distance between aircraft and person )

L²  =  x²  +  y²      or    L²  =  x²  + (405)²

Taken partial derivatives with respect to t we get:

2*L*δL/δt    =  2*x*δx/t + 0

Then      L*δL/δt = x*δx/dt

At the moment of the aircraft passing over the tower

x = 3040 ft       δx/δt = 640 ft/s   and L = √ ( 3040)² + (405)²

So   L  = √9241600  + 164025        L = √9405625   L ≈3066,9 ft

Then:

δL/δt = 3040*640/ 3066,9         units   [ ft * ft/s / ft ]   ft/s

δL/δt = 634,38 ft/s

5 0
3 years ago
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