I’m sorry I don’t know the length of JT however JE = 3.
Answer:
Step-by-step explanation:

Answer: D
Step-by-step explanation:
A) 3*0^2+2(0-5)>8
-10>8 -> not true
B) 3*(-1)^2+2(-1-5)>8
3*1+2*(-6)>8
3- 12>8
-9> 8 -> not true
C) 3*(-2)^2+2(-2-5)>8
3*4+2*(-7)>8
12-14>8
-2> 8 -> not true
D) ) 3*(-3)^2+2(-3-5)>8
3*9+2*(-8)>8
27-16>8
11> 8 -> true
ANSWER:
a = 11
b = 2
Explaination:
We have two equations:
a = 5b + 1 .....................(1)
a = 3b + 5.....................(2)
Here we use substitution method in order to solve the set of equations.
put a=3b+1 to equation (1)
3b + 5 = 5b + 1
Solve for b
5 = 5b -3b + 1
5-1 =2b
4 = 2b
b = 2
Now put the value of b = 2 into the equation (1) or (2)
a = 5b + 1
a = 5(2) + 1
a = 10 + 1
a = 11