Answer:
Step-by-step explanation:
100%
Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
9 inches
Step-by-step explanation:
Perimeter of equilateral triangle = 3x
Perimeter of square = 4x
3(x + 6) = 9 + 4x
3x + 18 = 9 + 4x
-x = -9
x = 9
The fractions would be in order-
3/10, 1/2, 4/5
Because if you change each fraction to a denominator of 10, the numbers will be 3/10, 5/10, and 8/10
Angle 4 is the same as angle 6, 75 degrees, there are alternate interior angles.
