The table and the graph below each show a different relationship between the same two variables, x and y: How much more would th
e value of y be on the graph than its value in the table when x = 12? (1 point) a 20 b 30 c 60 d 70
1 answer:
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Answer:
begin{aligned}
& x = \frac{D_x}{D} = \frac{-616}{-154} = 4 \\
& y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\
& z = \frac{D_z}{D} = \frac{-770}{-154} = 5
\end{aligned}
Step-by-step explanation:
Answer:
The probability that the HR director will select an employee who is not a multiple of 13 is
Step-by-step explanation:
* <em>Lets explain how to solve the problem</em>
- The probability of an event is the measure of the chance that the
event will occur
- The probability of an event A is the number of ways that event A can
occur divided by the total number of possible outcomes
- If P(A) is the probability of event A, is the probability that the event A
does not occur is 1 - P(A)
* <em>Lets solve the problem</em>
- An HR director numbered employees 1 through 50 for an extra
vacation day contest
∴ There are 50 employees
- The HR director will select an employee
- We need to find the probability of select an employees who is not
multiple of 13
* At first lets find the multiples of 13
∵ 13 × 1 = 13
∵ 13 × 2 = 26
∵ 13 × 3 = 39
∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39
∵ There are 3 multiples of 13
∵ There are 50 numbers
∵ Probability of multiple of 13 =
∵ Probability of not multiple of 13 = 1 - P(multiple of 13)
∴ Probability of not multiple of 13 =
∴ Probability of not multiple of 13 =
* The probability that the HR director will select an employee who is
not a multiple of 13 is