The answer is the third one (C?) because if you started at 0, you are going below it since you are losing yards, causing you to have less and less yards. Adding two negatives gives you a lesser amount.
1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
<h3>
Answer: Choice D) 31.2 miles</h3>
This value is approximate.
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Explanation:
Let's focus on the 48 degree angle. This angle combines with angle ABC to form a 90 degree angle. This means angle ABC is 90-48 = 42 degrees. Or in short we can say angle B = 42 when focusing on triangle ABC.
Now let's move to the 17 degree angle. Add on the 90 degree angle and we can see that angle CAB, aka angle A, is 17+90 = 107 degrees.
Based on those two interior angles, angle C must be...
A+B+C = 180
107+42+C = 180
149+C = 180
C = 180-149
C = 31
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To sum things up so far, we have these known properties of triangle ABC
- angle A = 107 degrees
- side c = side AB = 24 miles
- angle B = 42 degrees
- angle C = 31 degrees
Let's use the law of sines to find side b, which is opposite angle B. This will find the length of side AC (which is the distance from the storm to station A).
b/sin(B) = c/sin(C)
b/sin(42) = 24/sin(31)
b = sin(42)*24/sin(31)
b = 31.1804803080182 which is approximate
b = 31.2 miles is the distance from the storm to station A
Make sure your calculator is in degree mode.
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
237.3f= 1b. Explanation: is 712/3(237.3) so 1b is 237.3f