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BabaBlast [244]
3 years ago
9

Simon must maintain an average grade of 80% or better in his math class to be eligible to play sports.His math grade so far are

80%, 84%, 76%, 77% at this point his grades make him ineligible to play.What is the lowest he can score on the next grade to bring his average score up to 80%. Wright and inequality to represent the average of the five grades as greater than or equal to 80%. Use the Inequality To prove what his lowest score could be on the fifth test.
Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

Let x be the percentage score he got in fifth test,

According to the question,

His score in first, second, third and fourth test are 80%, 84%, 76% and 77% respectively,

Thus, the average of his total score in the five test,

= \frac{80+84+76+77+x}{5}

But, Again according to the question,

The average of the five grades as greater than or equal to 80%

That is,

\frac{80+84+76+77+x}{5}\geq 80

⇒ \frac{317+x}{5}\geq 80

⇒ 317 + x \geq 400

⇒ x\geq 83

Thus, the least score he can get in the fifth test is 83.

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y = .0775x + 700

y = .0775(4,000) + 700

y = 310 + 700

y = 1,010

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3 0
3 years ago
No idea what this means​
GenaCL600 [577]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4
lana66690 [7]
\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}
8 0
3 years ago
In the unit circle, the length of arc intercepted by an angle equals the radian measure of this angle. True False
Softa [21]
True. would be the righh answer
4 0
3 years ago
Plz help I will give anyone who answers this correctly 100 points.
dsp73

Answer:

126.

Step-by-step explanation:

Each rectangle is a step. We'll start with the top one. This is simple: 6 times 3.

6 * 3 = 18.

The farthest left is 5 times 3.

5 * 3 = 15.

The crossed one is 6 times 5.

6 * 5 = 30.

The one to the right of the crossed one is 3 times 5, again.

3 * 5 = 15.

The farthest right is 6 times 5, again.

6 * 5 = 30.

The bottom one is 6 times 3, again.

6 * 3 = 18.

Now, we add.

18 + 18 = 36.\\15 + 15 = 30.\\30 + 30 = 60.\\36 + 30 + 60 = 126.

8 0
3 years ago
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