Answer:
92.9997<
<99.5203
Step-by-step explanation:
Using the formula for calculating the confidence interval expressed as:
CI = xbar ± Z * S/√n where;
xbar is the sample mean
Z is the z-score at 90% confidence interval
S is the sample standard deviation
n is the sample size
Given parameters
xbar = 96.52
Z at 90% CI = 1.645
S = 10.70.
n = 25
Required
90% confidence interval for the population mean using the sample data.
Substituting the given parameters into the formula, we will have;
CI = 96.52 ± (1.645 * 10.70/√25)
CI = 96.52 ± (1.645 * 10.70/5)
CI = 96.52 ± (1.645 * 2.14)
CI = 96.52 ± (3.5203)
CI = (96.52-3.5203, 96.52+3.5203)
CI = (92.9997, 99.5203)
<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em>
<em><99.5203</em>
When eggs = 2, then potatoes = 5
Eggs: 2
Potatoes: 5
When that is changed to 6 eggs, 2 needs to be multiplied by a number to get 6.
2 * what = 6 or 6/2=
you get the number 3. A fraction is equivalent to a ratio. So if you have 2*3=6 then you need to multiply 5*3 to get the amount of potatoes you need. the answer is 15 potatoes because 5*3=15.
Using the given linear function of best-fit, the most likely approximate height of the plant after 8 weeks would be of 7.4 centimeters.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The line of best-fit goes through points (0,1) and (5,5). Point (0,1) means that the y-intercept is of b = 1. The slope is given as follows:
m = (5 - 1)/(5 - 0) = 4/5 = 0.8.
Hence the equation that gives the approximate height after x weeks is:
y = 0.8x + 1.
After 8 weeks, the expected height is:
y = 0.8 x 8 + 1 = 6.4 + 1 = 7.4 centimeters.
More can be learned about linear functions at brainly.com/question/24808124
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Given:
Speed limit on a highway is 110 km per hour.
Let x be the speed of the car in time 't'
![t\ge\frac{x}{110}](https://tex.z-dn.net/?f=t%5Cge%5Cfrac%7Bx%7D%7B110%7D)
time when taken for a car to travel 132km.
![\begin{gathered} t\ge\frac{132}{110} \\ t\ge1.2\text{ hours} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%5Cge%5Cfrac%7B132%7D%7B110%7D%20%5C%5C%20t%5Cge1.2%5Ctext%7B%20hours%7D%20%5Cend%7Bgathered%7D)
It takes minimum 1 hour 12 minutes