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3 years ago

Does anyone listen to Koe Wetzel?

Advanced Placement (AP)

2 answers:

siniylev [52]3 years ago

6 0

Answer:not really :c

Explanation:o

Ivan3 years ago

6 0

Nope not me!
What type of music is it?

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Are the elements of music present for every genere of music

zavuch27 [327]

Answer:

La música cuenta con cuatro elementos esenciales que son: el ritmo, la melodía, la armonía y los matices (Dinámica), aunque para algunos este último no es tenido en cuenta como tal. Otras propuestas adicionan la textura y la forma como un elemento

5 0

3 years ago

The equilateral triangular cross sections of a solid with base an arch of y = sin(x) on

olga nikolaevna [1]

We can define the base of each equilateral section as $b(x) = \sin(x)$ since this is the distance from the x-axis to the function $y=\sin(x)$ .

An equilateral triangle's area can have a function defined solely by the base. Since all sides are equal, the height of the triangle can be found via pythagorean theorem as: $A(b)=\frac{1}{2}b\sqrt{b^2+\left (\frac{b}{2} \right)^2} = \frac{b}{2}\sqrt{\frac{5b^2}{4}}$

But we know that the base $b(x)$ is a function of x. We also can then state that Area $A(b(x))$ is also a function of x. Specifically: $A(x) = \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}}$ .

Then if we integrate the area function A(x) from 0 to pi, we get the total volume:

$\displaystyle \int_0^{\pi} A(x) dx = \int_0^{\pi} \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}} dx = \int_0^{\pi} \frac{\sqrt{5} \sin^2(x)}{4}dx$

7 0

4 years ago

Which equation represents the table:

icang [17]

Answer:

Y=x+6

Explanation:

It sums it all up together

3 0

3 years ago

ASAP HELP PLEASE 20 points

vladimir2022 [97]

The first statement is correct. The second statement is incorrect because it says 3 moles of oxygen instead of dioxide. The third one is incorrect because it’s telling weights not moles

4 0

3 years ago

Read 2 more answers

The mass of the Sun is 2 × 1030 kg, and the distance between Neptune and the Sun is 30 AU. What is the orbital period of Neptune

Volgvan

<h2>Orbital Period:</h2>

To answer this problem, we must employ the gravitational notion and equation. We already know that gravitational force provides the required centripetal force for orbital motion. As a result of matching gravitational and centripetal forces, we may get the equation for orbital time period.

<h2>Answer and Explanation:</h2><h3>Given:</h3>

Mass of Sun (M) = 1.99 * 10^30 Kg
Orbital radius of the Neptune
(R) = 30 A.U. = 30 * (1.496 * 10^11) m
R = 44.88 * 10^11 m

Now we know that the time period is given by

T^2 = 4π^2R^3/GM

T^2 = 4π^2*(44.88*10^11)^3/6.67*10^-11*(1.99*10^30)

T = 5.19 * 10^9 s

Now we know that

1 year = 3.154 * 10^7 s

Therefore, T = 5.19*10^9 s/ 3.154 * 10^7 (s/year)

T = 164.4 year

3 0

2 years ago