Answer:
d po yung answer
Step-by-step explanation:
sana makatulong
Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
The correct answer for the question that is being presented above is this one:
We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>
<span>Then set that equation equal to your solubility constant </span>
<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3
</span>
<span>So the molar solubility is 9.67x10-3</span>
