What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
The whole ends up being 42 ft².
Area of a triangle = 1/2 * base * height.
So that lil triangle piece is 1/2 * 2 * 3 = 1/2 * 6 = 3
Now we do the rectangle piece. Area of a rectangle = length * width
So that rectangle is 3 * 7 = 21
If you take away those two, you are left with a trapezoid.
Area of a trapezoid is 1/2 * (base 1 + base 2) * height
Base 1 is the width of the rectangle which is 3. Base 2 is the 6. The height is the given 11 feet minus the 7 feet from the length of the rectangle which is 4.
Plug all this in to the formula you get 1/2 * (6 + 3) * 4 = 1/2 * 9 * 4 = 1/2 * 36 = 18.
Now add all of your areas together;
21 + 3 + 18 = 24 + 18 = 42
Answer:
Just put 4 basketballs and 5 baseballs in each one
Step-by-step explanation:
If you think about it you will know that each ratio there is the same. So, you do the same thing each time.
All you have to do now is read. It says put 4 basketballs and 5 baseballs.
I hope this helped ;)
