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Arturiano [62]
4 years ago
7

Plz help with all of it !

Mathematics
1 answer:
DiKsa [7]4 years ago
6 0
1)

a) 3/9= 0.333333333333 but you can just say 0.3
b) 4/3= 1.333333333333 but you also can say 1.33 or just 1.3

2)

a) 21/8, 21 over 8 if you solve you would get 2.625
b) 7(divide sign)4, which is also 7/4, if you solve you would get 1.75
c) 4/9 , 4 over 9 if you solve you would get 0.444444444 which is 0.4
d) 9/7, 9 over 7, if you solve it would be 1.285 which is 1.3


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(2.6 x 106) + (4.2 x 106)
riadik2000 [5.3K]

Answer:

720.8

Step-by-step explanation:

(2.6 × 106) + (4.2 × 106)

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4 years ago
In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume
kobusy [5.1K]

Answer:

The probability that the total weight of the passengers exceeds 4222 pounds is 0.0018

Step-by-step explanation:

The Central limit Theorem stays that for a large value of n (21 should be enough), the average distribution X has distribution approximately normal with mean equal to 182 and standard deviation equal to 30/√21 = 6.5465. Lets call W the standarization of X. W has distribution approximately N(0,1) and it is given by the formula

W = \frac{X - \mu}{\sigma} = \frac{X - 182}{6.5465}

In order for the total weight to exceed 4222 pounds, the average distribution should exceed 4222/21 = 201.0476.

The cummulative distribution function of W will be denoted by \phi . The values of \phi can be found in the attached file.

P(X > 201.0476) = P(\frac{X-182}{6.5465} > \frac{201.0476 - 182}{6.5465}) = P(W > 2.91) = 1-\phi(2.91) = \\1-0.9982 = 0.0018

Therefore, the probability that the total weight of the passengers exceeds 4222 pounds is 0.0018.  

Download pdf
6 0
4 years ago
What is the standard form of -9+8x=-10y
Nitella [24]
<span><span>8x</span>+<span>10y</span></span>=<span>9

Hope this helps.</span>
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3 years ago
Read 2 more answers
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