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zloy xaker [14]
3 years ago
15

Quadrilateral ABCD has the following coordinates:

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

A¹ (3 , -1) , B¹(0,-8) , C¹(8,-9) , D¹(7,-2)

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given coordinates are

  A(1,3) ,B(8,0) ,C( 9,8) ,D(2,7)

The coordinates are rotating the shape 90° clockwise then the transformed to (x,y)→ (y ,-x)

The new coordinates

A(1,3) → A¹ (3 , -1)

B(8,0) →  B¹(0,-8)

C(9,8) →  C¹(8,-9)

D(2,7) →   D¹(7,-2)

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The diagram shows a 5 cm x 5 cm x 5 cm cube.
mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

5 0
2 years ago
Read 2 more answers
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vodka [1.7K]
3x + 2y = 12
subtract 3x from both sides
2y = -3x + 12
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3 years ago
Please please help me with this
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Answer:

c

Step-by-step explanation:

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While the line on the right has an open circle at x = 1 indicating it is defined for x > 1

Both line segments have a negative slope, thus

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d1i1m1o1n [39]
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3x + y = 5<br><br> 2x - 2y = -2
Vesnalui [34]

Answer:

Solving the system of equations:

x: 1

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Step-by-step explanation:

Plug it in to see if it is right, to make sure of course.  Better to be safe than sorry.

7 0
2 years ago
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