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lesya [120]
3 years ago
5

6/4 + 2/7 fracciones con diferente denominador

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

1 and 22/28 = 1 and 11/14

Step-by-step explanation:

<h2>6/4= 42/28</h2><h2>2/7= 8/28</h2><h2 /><h2>8/28 + 42/28 = 50/28</h2><h2 /><h2>50/28= 1 and 22/28 simplifies to 1 and 11/14</h2>
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Identify the factors of the terms of the expression of 13m-2n
Alex Ar [27]
Hi it is 7n I hope I was right
4 0
3 years ago
A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten
AfilCa [17]

Answer:

<em>35.11 ft</em>

<em></em>

Step-by-step explanation:

This given situation can be thought of as triangle \triangle PQR where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And \angle Q \neq 90^\circ

Given that:

PQ = 44 ft

PR = 51 ft

\angle R = 58^\circ

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ

Now,

\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ

Let us use the Sine rule again:

\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft

So, the answer is <em>35.11 ft</em>.

3 0
3 years ago
Is the line through points P(2, –5) and Q(–5, –1) parallel to the line through points R(5, 4) and S(–2, 5)? Explain.
Irina-Kira [14]

Answer:

the answer is No

Step-by-step explanation:

Since the first line has a slope of -4/7 and the other line has a slope of -1/7. This can be shown in point slope form y-y1=m(x-x1) where m=∆y/∆x.

Through points P and Q, the point slope is represented as -1-(-5)=m(-5-2) ; 4 = -7m ; m = 4/-7. The next two points R and S can be shown in point slope as 5-4=m(-2-5) ; 1 = -7m ; m =1/-7. With the fact that parallel lines must have equal slopes, these two lines cannot be parallel because -4/7≠-1/7

3 0
3 years ago
Can someone please help
Sliva [168]

Answer:

i got no clue

Step-by-step explanation:

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4 0
3 years ago
Dimension of triangle A are three times the dimensions of triangle
nikitadnepr [17]
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8 0
3 years ago
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