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3 years ago

Which expression is equivalent to (4x^3y^5)(3x^5y)^2 ?

Mathematics

1 answer:

barxatty [35]3 years ago

3 0

(3x^5y)^2=

3^2=9

(x^5)^2=x^10

y^2=y^2

(3x^5y)^2=9x^10y^2

9x^10y^2(4x^3y^5)=

9*4=36

x^10*x^3=x^13

y^2*y^5=y^7

9x^19y^2(4x^3y^5)= 36x^13y^7

Final answer: 36x^13y^7

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9s - 5g = -4y, for s

Oksi-84 [34.3K]

S = (5g -4y)/9

hope this helps

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4 years ago

Angles T and V are country that angle T has a measure of (2X +10) angle B has a measure of 48° what is the value of X

enyata [817]

If T and V are complementary angles, their sum is 90°.

V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2

The value of X is 16.

4 0

3 years ago

In a group of 10 kittens, 5 are female. Two kittens are chosen at random. a) Create a probability model for the number of male

olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ± $\frac{2}{3}$ .

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

So, total number of kitten = 10

number of female kitten = 5

then, Number of male kitten = $10-5= 5$

Now total number of ways to choosing two kittens from group of 10 = $^{10} C_{2}$

= $\frac{10!}{2!\times8!}$

= $45$

for choosing (i) No male P(x=0) = P(Two female) = $\frac{^{5} C_{2}}{45}$

= $\frac{2}{9}$

(ii) 1 male P(x=1) = P(1 male and 1 female) = $\frac{^{5} C_{1}\times^{5} C_{1}}{45}$ = $\frac{25}{45}$ = $\frac{5}{9}$

(iii) 2 male P(x=2)= P(2 male) = $\frac{^{5} C_{2}}{45}$ = $\frac{2}{9}$

$x_{i}$ 0 1 2

P(X= $x_{i}$ ) $\frac{2}{9}$ $\frac{5}{9}$ $\frac{2}{9}$

(b) what is expected number of male kittens chosen ?

Expected number of male kitten E(x) = $o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}$

= $1$

(c) what is standard deviation ?

$\sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})$

No,

$Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}$

= $\frac{13}{9}$

$\sigma(x)=\sqrt{\frac{13}{9} - 1 }$ $=\sqrt{\frac{4}{9} }$

= ± $\frac{2}{3}$

6 0

3 years ago

Simplify 6r · s · 4rt. 10rst

Scrat [10]

If the problem is 6r•s•4rt•10rst, then the answer is 240•r^3•s^2•t^2.

4 0

3 years ago

Read 2 more answers

Solve for x. x−1/4=3/8

valentinak56 [21]

x=5/8 is the correct answer. First you had to simplify from both sides of equation, and it gave us, $x+\frac{-1}{4}=\frac{3}{8}$ . Then you add 1/4 from both sides of equation, and it gave us, $x+\frac{-1}{4}+ \frac{1}{4}= \frac{3}{8}+ \frac{1}{4}$ . And it gave us the answer is x=5/8 is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

3 0

3 years ago