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Romashka [77]
3 years ago
7

What is the square root of 1/9?

Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

\frac{1}{3}

Step-by-step explanation:

\sqrt{\frac{1}{9} } = \sqrt{\frac{1}{3} } {^{2}  } \\\\=\frac{1}{3}

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the first number in a pattern is 6. the pattern follows the rule divide by 2. the add 8. complete the table to show the next thr
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First 6, then 11, then 13.5, then (honestly I don't know the rest). '__'
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3 years ago
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This right rectangular prism is filled with -foot unit cubes.
KonstantinChe [14]

Answer:

The answer would be 36.

Step-by-step explanation:

3x3x9 is 36ft.

5 0
3 years ago
Derive a formula for the bullet speed v in terms of D, T, and a measured angle θ between the position of the hole in the first d
Ad libitum [116K]

Answer:

θ = 2π

Rotational period = T

so the angular velocity is:

w=2πT

v=Dt

D=vt

Step-by-step explanation:

3 0
3 years ago
standard automobile license plates in a country display 3 numbers, followed by 2 letters, followed by 2 numbers. how many differ
RoseWind [281]

The system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

<h3>Define the term permutation?</h3>
  • The number of potential arrangements for a given set is assessed mathematical terms, but this procedure is referred to as permutation.
  • The arrangement's order is essential when using permutations.

For the stated data;

Standard car license plates in a nation typically have 3 digits, 2 letters, and 2 numbers.

There are total 9 digits (0 - 9).

There are total 26 letter (A - Z)

Repetitions of letters and numbers given allowed.

Thus, numbers and the letters ca be arranged as;

1st place = 9 ways.

2nd place = 9 ways.

3nd place = 9 ways.

4th place = 26 ways.

6th place = 26 ways.

7th place = 9 ways.

8th place = 9 ways.

Total ways = 9×9×9×26×26×9×9

Total ways = 39917124

Thus, the system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

To know more about the permutation, here

brainly.com/question/1216161

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5 0
1 year ago
Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation
KatRina [158]

Answer:

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB) = 0.27

Step-by-step explanation:

<u>Explanation</u>:-

<u>Addition theorem on probability</u>:-

If S is a sample space, and E , F are any events in S then

P(EUF) = P(E) +P(F) -P(E n F)

Let 'E' be the event that a corn crop has an infestation of ear worms

let 'B' be the event that a corn crop has an infestation of corn bores

P(EUB) = P(E) +P(B) -P(E n B)

given P(E) = 0.24 and P(B) = 0.16 and P(E n B) =0.13

P(EUB) = P(E) +P(B) -P(E n B)

P(EUB) = 0.24 + 0.16 - 0.13

           = 0.27

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB)=0.27

7 0
4 years ago
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