Answer:
Step-by-step explanation:
. cubesi, 20,64. AV 1,6,11,16... Add 5. 1, 2, 4, 8. . Multiply 2. $2,9,28,65... cubes add 1. 31,49,16 ...
Ok this is the answer to this question 2(x+1)
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
X^3 + 8 =
<span>factorized
( x + 2 )</span><span>( <span><span>x2− 2x </span>+ 4 </span><span>)
</span></span>
Answer:
r =
Step-by-step explanation:
r=30√12,−30√12
