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Fiesta28 [93]
4 years ago
12

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

nd C′(15, 0)-. The origin is the center of dilation. What is the scale factor of the dilation?
Mathematics
2 answers:
Cerrena [4.2K]4 years ago
6 0
K · ( 0, 0 ) = ( 0 , 0 )
k · ( 0 , 4 ) = ( 0 , 10 )
k · ( 6, 0 ) = ( 15, 0 )
k = 15/6 = 10/4 = 2.5
Answer: The scale of dilation is 2.5
LenKa [72]4 years ago
6 0

The answer would be c 2.5

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Dawson rakes leaves in his neighborhood. The equation y = 10x represents the amount of money he earns. What is the constant of p
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3 years ago
8 + 8r = 3 + 3r can anyone can help me out​
MAVERICK [17]

Answer:r = -1

Step-by-step explanation:

8+8r-(3+3r)=0

We add all the numbers together, and all the variables

8r-(3r+3)+8=0

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8r-3r-3+8=0

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6 0
3 years ago
Read 2 more answers
Identify the two triangle congruence criteria that do NOT guarantee congruence. Explain why they do not guarantee congruence, an
Mashcka [7]

Answer: Hello mate!

there are two congruence criteria that do not guarantee congruence:

AAA ( or 3 angles)

two triangles can have the same 3 angles, but different size, then they are not congruent; an example of this is:

take the triangle rectangle of both cathetus = 1 and hypotenuse = √2, where the angles are 90°, 45° and 45°

and now take the triangle rectangle with both cathetus = 2 and hypotenuse = √8, this triangle also has the angles 90°, 45°, and 45°, so this two triangles succeed the AAA criteria, but are not congruent.

SSA (side-side-angle)

If two triangles satisfy the SSA  criteria and the corresponding angles are acute and the length of the side opposite to the angle is greater than the length of the adjacent side multiplied by the sine of the angle (but less than the length of the adjacent side), then the two triangles are not necessarily congruent.

This is kinda harder to illustrate;  

think on a triangle rectangle where you have the measure of both cathetus and one of the angles different from 90° as the SSA data.

and now think on another triangle that has the same adjacent cathetus and angle, and where the other cathetus is rotated (in a sense where 90° is decreasing) to the point where its tip intercepts the hypotenuse of the first triangle.

Those two triangles meet the SSA criteria but are not congruent.

7 0
3 years ago
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0
3 years ago
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