A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
2 answers:
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First, you must convert the decimals to have the same denominator.
Find the least common multiple of both fractions' denominators:
Multiples of 8: {8,16,24,32,40}
Multiples of 10: {10,20,30,40}
The least common multiple of 8 and 10 is 40.
Multiply the fractions by a number that will make their denominator 40:
Now you can add these fractions together:
Simplify this fraction:
The answer should be 1/8.
Find the least common multiple of both fractions' denominators:
Multiples of 8: {8,16,24,32,40}
Multiples of 10: {10,20,30,40}
The least common multiple of 8 and 10 is 40.
Multiply the fractions by a number that will make their denominator 40:
Now you can add these fractions together:
Simplify this fraction:
The answer should be 1/8.
Answer:
B. x^2
Step-by-step explanation:
If m = x/y and
n = 1/xy
then
m/n = (x/y)/(1/xy)
You can simplify this complex fraction (fraction over a fraction) with the method Keep-Change-Flip. It works!
KEEP x/y
CHANGE ÷ to ×
FLIP 1/xy over to be xy/1
See image.
x/y • xy/1
= x^2
