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julia-pushkina [17]
3 years ago
14

Please answer as many as you can from problems 2-8

Mathematics
1 answer:
klasskru [66]3 years ago
3 0
W0W alot........
2. 16/5c
3. 3q/2r^2
4. 1
5. yw^2/z^3x^3
6. 20j
7. 0 + m^2-m+m+1/m^2-m
8. 1- 1/b+2
H0P3 It H3LPS :)
#Itwashardwork

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I have no idea how to answer this. please help me
Anastasy [175]

Answer:

The perimeter is 36.

Step-by-step explanation:

You can see that the sides labeled are the same length as another side. And to get the perimeter you have to do 8+10+8+10=36

4 0
3 years ago
I need help please !
xxTIMURxx [149]

Answer:

72 + 12 / 35 + 7

84 / 42

2

hope it helps

7 0
3 years ago
Read 2 more answers
Fill in the missing numbers<br>I need an answer ASAP<br><br>​
mamaluj [8]

Answer:

the missing numbers be 60 and 6 respectively

Step-by-step explanation:

The computation of the missing numbers are shown below:

Let us assume the missing numbers be x

a/

, \frac{1}{2} \times 30 =  \frac{1}{4} \times x\\\\15 =    \frac{1}{4} \times x\\\\x = 60

b.

\frac{1}{3} \times 12 =  \frac{2}{3} \times x\\\\4 =    \frac{2}{3} \times x\\\\x = 6

Hence, the missing numbers be 60 and 6 respectively

4 0
3 years ago
a cone has a radius of 6cm and height 9 calculate a)the volume and curved surface area b) total surface area
Orlov [11]

Answer:

V = 339.3 cm³; L = 203.9 cm²; A = 317.0 cm²  

Step-by-step explanation:

a) Volume

The formula for the volume (V) of a cone is

V = ⅓πr²h

V = ⅓π × 6² × 9

V = ⅓π × 36 × 9

V = 108π cm³

V ≈ 339.3 cm³

=====

Curved surface area  

The formula for the lateral surface area (L) of a cone is

L = πr√(r² + h²)

L = π×6√(36 + 81)

L = 6π√[9(4 + 9)]

L = 6π√(9 × 13)

L = 18π√13 cm²

L ≈ 203.9 cm²

===============

b) Base surface area

The base is a circle, so the formula for base surface area (B) is

B = πr²

B = π×6²

B = 36π cm²

B ≈ 113.1 cm²

=====

Total surface area

A = L + B

A = 18π√(13 +36π)

A = 18π(2 + √13) cm²

A ≈ 203.9 + 113.1

A ≈ 317.0 cm²

3 0
3 years ago
A cube-shaped aquarium has edges that are 3 feet long and is filled with water that has a density of 62 lbs/ft3 Should the aquar
Sunny_sXe [5.5K]

Given:

There are given the edge of the cube-shaped aquarium has 3 feet.

Explanation:

To find the value, we need to use the volume of the cube formula:

So,

From the formula of volume:

V=a^3

Where

a represents the value of edge.

So,

Put the value of edge into the above formula:

Then,

\begin{gathered} V=a^3 \\ V=3^3 \\ V=27cube\text{ feet} \end{gathered}

Now,

The water has a density of 62 pounds per cube foot.

According to the question:

If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

62\times27=1674pound

Final answer:

Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.

And,

No, the density of water would not change.

6 0
1 year ago
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